import datetime
year = 2000
month = 1
day = 1
c = 0
date = datetime.date(year, month, day)
for i in range(200000):
weekday = date.weekday()
day = date.day
month = date.month
year = date.year
if year>2099:
break
weekday_names = ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday']
if day==13 and weekday_names[weekday] == 'Friday':
print(f"{c}: {year}/{month}/{day} is a {weekday_names[weekday]}")
c = c + 1
date = date + datetime.timedelta(days=1)
