使用遞迴控制列印次數

 def f(n):

print('i love python')

if n==1:return 

return f(n-1)

n = int(input())

f(n)

Python sys.getsizeof()

 import sys

print('bool:',sys.getsizeof(True) )

print('char:',sys.getsizeof('a') )

print('short:',sys.getsizeof(1) )

print('int:',sys.getsizeof(65537) )

print('float:',sys.getsizeof(1048577) )

print('double:',sys.getsizeof(1.1) )

bool: 28↵\r\n

char: 42↵\r\n

short: 28↵\r\n

int: 28↵\r\n

float: 28↵\r\n

double: 24↵\r\n

graph has loop ?

 #d = [[0,1],[1,2],[2,3],[3,4]] # no loop

d = [[0,1],[1,2],[2,3],[3,2]]

node = []

edge = []

for i in d:

    node.append(i[0])

    node.append(i[1])

    edge.append([i[0],i[1]])

  

node = set(node)

#edge = set(edge)

links = []

for i in node:

    t =str(i)

    for j in edge:

        if j[0]==i:

           t = t + str(j[1]) 

    links.append(t)

links1 = []

for i in links:

    t = i

    for j in edge:

        if i[-1] == str(j[0]):

            t = t + str(j[1])

    links1.append(t)

links2 = []

for i in links1:

    t = i

    for j in edge:

        if i[-1] == str(j[0]):

            t = t + str(j[1])

    links2.append(t)

    

for i in links2:

    if len(list(i))!=len(set(i)):

        print(i,':loop')